Odpowiedź:
c) [tex]\frac{18}{2x - 6} / \frac{-3}{4x-12} = \frac{18}{2x - 6} * \frac{4x-12}{-3} = \frac{18*(4x-12)}{(2x-6)*(-3)} = \frac{72x - 216}{-6x + 18} = \frac{72(x-3)}{-6(x-3)}[/tex]
d) [tex]\frac{-6}{3-2x} / \frac{9}{4x - 6} = \frac{-6}{3-2x} * \frac{4x - 6}{9} = \frac{-6*(4x-6)}{(3-2x)*9} = \frac{-24x+36}{27-18x} = \frac{4x-4}{3-3x} = \frac{4(x-1)}{3(1-x)}[/tex]
e) [tex]\frac{9x}{2x+4} / \frac{6}{x+2} = \frac{9x}{2x+4} * \frac{x+2}{6} = \frac{9x*(x+2)}{(2x+4)*6} = \frac{9x^{2}+18}{12x+24} = \frac{3(3x^{2}+6)}{12(x+12)} = \frac{1(3x^{2}+6)}{4(x+12)}[/tex]
f) [tex]\frac{10x^{2}}{x-5} / \frac{5}{10 - 2x} = \frac{10x^{2}}{x-5} * \frac{10 - 2x}{5} = \frac{10x^{2}*(10-2x)}{(x-5)*5} = \frac{100x^{2}-20x^{3}}{5x - 25} = \frac{5x^{2}(20-x)}{5(x-5)}[/tex]