Odpowiedź :
a) w(x) = x²(x-4) + 1(x-4) = (x-4)(x²+1)
b) w(x) = 2[tex]x^{4}[/tex](2x-1) - 8x²(2x-1) = (2x-1)(2[tex]x^{4}[/tex]-8x²) = 2x²(2x-1)(x²-4) =
= 2x²(2x-1)(x-2)(x+2)
a) w(x) = x²(x-4) + 1(x-4) = (x-4)(x²+1)
b) w(x) = 2[tex]x^{4}[/tex](2x-1) - 8x²(2x-1) = (2x-1)(2[tex]x^{4}[/tex]-8x²) = 2x²(2x-1)(x²-4) =
= 2x²(2x-1)(x-2)(x+2)