[tex]dane:\\V = 1,6 \ cm^{3}\\d = 10,5\frac{g}{cm^{3}}\\szukane:\\m = ?\\\\Rozwiazanie\\\\d = \frac{m}{V} \ \ /\cdot V\\\\m = V\cdot d\\\\m = 1,6 \ cm^{3}\cdot10,5\frac{g}{cm^{3}}\\\\m = 16,8 \ g \ \approx17 \ g\\\\Odp. \ d)[/tex]
