Odpowiedź :
[tex]\frac{3^{2}}{3} =\frac{9}{3} = 3\\\\\frac{2^{2}}{3} = \frac{4}{3} = 1\frac{1}{3}\\\\3,5+8 = 13,5\\\\\frac{4}{17}-\frac{17}{17} = -\frac{13}{17}\\\\2,9-1,2 = 1,7[/tex]
[tex]\frac{3^{2}}{3} =\frac{9}{3} = 3\\\\\frac{2^{2}}{3} = \frac{4}{3} = 1\frac{1}{3}\\\\3,5+8 = 13,5\\\\\frac{4}{17}-\frac{17}{17} = -\frac{13}{17}\\\\2,9-1,2 = 1,7[/tex]