Odpowiedź :
[tex]Dane:\\m = 0,2 \ kg\\r = 1 \ m\\v = 20\frac{m}{s}\\Szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r}\\\\F_{d} = \frac{0,2 \ kg\cdot(20\frac{m}{s})^{2}}{1 \ m}\\\\\boxed{F_{d} = 80 \ N}[/tex]
[tex]Dane:\\m = 0,2 \ kg\\r = 1 \ m\\v = 20\frac{m}{s}\\Szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r}\\\\F_{d} = \frac{0,2 \ kg\cdot(20\frac{m}{s})^{2}}{1 \ m}\\\\\boxed{F_{d} = 80 \ N}[/tex]