1.
[tex]Dane:\\m = 2 \ kg\\h = 1,5 \ m\\g = 10\frac{m}{s^{2}}\\Szukane:\\W = ?[/tex]
Praca równa jest energii potencjalnej ciężkości:
[tex]W = E_{p} = mgh\\\\W = mgh\\\\W = 2 \ kg\cdot10\frac{m}{s^{2}}\cdot1,5 \ m\\\\\boxed{W = 30 \ J}[/tex]
2.
[tex]Dane:\\m = 2 \ kg\\g = 10\frac{m}{s^{2}}\\s = 10 \ m\\Szukane:\\W = ?\\\\\\W = F\cdot s\\\\ale \ \ F = m\cdot g\\\\W = m\cdot g\cdot s\\\\W = 2 \ kg\cdot10\frac{m}{s^{2}}\cdot10 \ m\\\\\boxed{W = 200 \ J}[/tex]
