Odpowiedź:
a) a=2dm
h=0,5m=5dm
Pc=2Pp+Ppb=2a²+4ah
[tex]pc = 2 \times {2}^{2} + 4 \times 2 \times 5 = 8 + 40 = 48 {dm}^{2} [/tex]
b) a=6
h=0,8dm=8cm
Pc=[2*a²✓3]/4 +3a*h
[tex]pc = 2 \times \frac{ {6}^{2} \sqrt{3} }{4} + 3 \times 6 \times 8 = 18 \sqrt{3 } + 144 = 18( \sqrt{3} + 8) \: {cm}^{2} [/tex]
c) a=4cm=40mm
h=45mm
Pc=[3a²✓3]/2 +6a*h
[tex]pc = 2 \times \frac{3 \times {40}^{2} \sqrt{3} }{2} + 6 \times 40 \times 45 = 4800 \sqrt{3 } + 10800 = 15600 \: {mm}^{2} [/tex]
