proszę o pilną pomoc!!!

Odpowiedź:
[tex]\frac{x}{2}- \frac{y}{3}=1[/tex] |*6
[tex]\frac{x}{4}+\frac{2y}{3}=8[/tex] |*12
(metoda przeciwnych współczynników)
3x - 2y = 6 |*4
3x + 8y = 96
12x - 8y = 24
3x + 8y = 96
12x + 3x - 8y + 8y = 24 + 96
15x = 120 |:15
x = 8
[tex]\frac{x}{2}-\frac{y}{3}=1[/tex] dla x = 8
[tex]\frac{8}{2}-\frac{y}{3}=1[/tex]
[tex]4-\frac{y}{3}=1[/tex] |-4
[tex]-\frac{y}{3}=-3[/tex] |*(-3)
y = 9
x = 8
y = 9
Szczegółowe wyjaśnienie:
[tex] \begin{cases} \frac{x}{2} - \frac{y}{3} = 1 | \times 6\\ \frac{x}{4} + \frac{2y}{3} = 8 | \times 12 \end{cases}[/tex]
[tex] \begin{cases} 3x - 2y = 6 | \times 4 \\ 3x + 8y = 96\end{cases}[/tex]
[tex] \begin{cases} 12x - 8y = 24 \\ 3x + 8y = 96\end{cases}[/tex]
[tex]12x + 3x = 24 + 96 \\ 15x = 120 | \div 15 \\ x = 8[/tex]
[tex]3 \times 8 + 8y = 96 \\ 24 + 8y = 96 \\ 8y = 72 | \div 8 \\ y = 9[/tex]
[tex] \begin{cases}x = 8 \\ y = 9 \end{cases}[/tex]