[tex]d = 10\sqrt{3} \\e = 16\\P = 40\sqrt{6}[/tex]
α = ?
[tex]P = \frac{1}{2} * d * e * sin\alpha \\40\sqrt{6} = \frac{1}{2} * 10\sqrt{3} * 16 * sin\alpha\\80\sqrt{6} = 10\sqrt{3} * 16 * sin\alpha\\80\sqrt{6} = 160\sqrt{3} * sin\alpha\\sin\alpha = \frac{80\sqrt{6} }{160\sqrt{3} } \\sin\alpha = \frac{80\sqrt{2} }{160} \\sin\alpha = \frac{\sqrt{2} }{2} \\[/tex]
α = 45°
Odp: B
