Odpowiedź :
Krawędź sześcianu
[tex]a \sqrt{2} = 8 \\ a = \frac{8}{ \sqrt{2} } = \frac{8 \sqrt{2} }{2} = 4 \sqrt{2} cm[/tex]
Objętość
[tex](4 \sqrt{2} {)}^{3} = 64 \times \sqrt{8} = 64 \times 2 \sqrt{2} = \underline{ 128 \sqrt{2} {cm}^{3} }[/tex]
Pole całkowite
[tex]6 \times (4 \sqrt{2} {)}^{2} = 6 \times 16 \times 2 = 6 \times 32 = \underline{ 192 {cm}^{2} }[/tex]