Odpowiedź:
I.
-9(2 + y) - 3y + 8 = -2(4y + 5)
- 18 - 9y - 3y + 8 = -8y - 10
- 4y = 0
y = 0
III.
[tex]\frac{-9(1+3x)}{2}+1 = 3(-3 + 2x)[/tex]
-9(1 + 3x) + 2 = - 18 + 12x
- 9 - 27x + 2 = - 18 + 12x
-39x = - 11
[tex]x = \frac{11}{39}[/tex]
