[tex]Dane:\\m = 680 \ g = 0,68 \ kg\\F = 6 \ N\\Szukane:\\a = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m}\\\\a = \frac{6 \ N}{0,68 \ kg} = \frac{6 \ kg\cdot\frac{m}{s^{2}}}{0,68 \ kg}\\\\\boxed{a\approx8,82\frac{m}{s^{2}}}[/tex]
