Odpowiedź :
[tex]|\Omega|=8\cdot7=56\\A=\{(1,2),(1,5),(2,4),(2,7),(3,6),(4,5),(5,7),(7,5),(5,4),(6,3),(7,2),(4,2),\\(5,1),(2,1)\}\\|A|=14\\P(A)=\dfrac{14}{56}=\dfrac{1}{4}[/tex]
[tex]|\Omega|=8\cdot7=56\\A=\{(1,2),(1,5),(2,4),(2,7),(3,6),(4,5),(5,7),(7,5),(5,4),(6,3),(7,2),(4,2),\\(5,1),(2,1)\}\\|A|=14\\P(A)=\dfrac{14}{56}=\dfrac{1}{4}[/tex]