Odpowiedź :
5.
[tex]Dane:\\V = 0,000125 \ m^{3}\\d = 920\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 920\frac{lg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,000125 \ m^{3}\\\\\boxed{F_{w} = 1,15 \ N}[/tex]
6.
[tex]Dane:\\F = 200 \N\\S = 0,5 \ m^{2}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\p = \frac{200 \ N}{0,5 \ m^{2}}\\\\\boxed{p = 400 \ Pa}[/tex]
7.
[tex]Dane:\\h = 5 \ m\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\p=?\\\\Rozwiazanie\\\\Cisnienie \ hydrostatyczne:\\\\p = d\cdot g\cdot h\\\\p = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot 5 \ m\\\\\boxed{p = 50 \ 000 \ Pa = 50 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]