Odpowiedź :
[tex]|\Omega|=7\\|A|=4\\\\P(A)=\dfrac{4}{7}[/tex]
[tex]\dfrac{4}{7}=\dfrac{16}{28}\\\\\dfrac{1}{2}=\dfrac{14}{28}\\\\\dfrac{1}{4}=\dfrac{7}{28}[/tex]
Widzimy, że [tex]\dfrac{4}{7}>\dfrac{1}{2}>\dfrac{1}{4}[/tex], zatem D.
[tex]|\Omega|=7\\|A|=4\\\\P(A)=\dfrac{4}{7}[/tex]
[tex]\dfrac{4}{7}=\dfrac{16}{28}\\\\\dfrac{1}{2}=\dfrac{14}{28}\\\\\dfrac{1}{4}=\dfrac{7}{28}[/tex]
Widzimy, że [tex]\dfrac{4}{7}>\dfrac{1}{2}>\dfrac{1}{4}[/tex], zatem D.