Odpowiedź :
[tex](3+ \frac{1}{5} ):( \frac{3}{5} -\frac{1}{3} )=3\frac{1}{5} :(\frac{9}{15} -\frac{5}{15} )=3\frac{1}{5} :\frac{4}{15} =\frac{16}{5} :\frac{4}{15} =\frac{\not16}{\not5} \cdot\frac{\not15}{\not4} =4\cdot3=\boxed{12}[/tex]
[tex](3+ \frac{1}{5} ):( \frac{3}{5} -\frac{1}{3} )=3\frac{1}{5} :(\frac{9}{15} -\frac{5}{15} )=3\frac{1}{5} :\frac{4}{15} =\frac{16}{5} :\frac{4}{15} =\frac{\not16}{\not5} \cdot\frac{\not15}{\not4} =4\cdot3=\boxed{12}[/tex]