[tex]d)\\\\-(\sqrt{17})^2-(\sqrt{24})^2=-17-24=-41\\\\\\e)\\\\(\sqrt[3]{4})^3+\sqrt[3]{125}:(-5)=4+5:(-5)=4-1=3\\\\\\f)\\\\\sqrt[3]{\frac{1}{125}}-(\sqrt[3]{\frac{1}{5}})^3=\frac{1}{5}-\frac{1}{5}=0[/tex]
[tex]stosujemy\ wzory:\\\\(\sqrt{a})^2=a\\\\(\sqrt[n]{a})^n=a[/tex]
