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Obliczenia
[tex]m_\text{C}=12 \ u\\\\m_{\text{H}}=1 \ u\\\\m_{\text{O}}=16 \ u\\\\m_{\text{C}_6\text{H}_{12}\text{O}_6}=12 \ u\cdot6+1 \ u\cdot12+16 \ u\cdot6=72 \ u+12 \ u+96 \ u=\boxed{180 \ u}[/tex]
Odpowiedź:
mC=12u, mH=1u, mO=16u
mC6H12O6= 6× 12u+ 12× 1u+ 6× 16u= 72u+ 12u+ 96u= 180u
Wyjaśnienie:
