zad 2 i 3, twierdzenie pitagorasa

Zad 2 I 3 Twierdzenie Pitagorasa class=

Odpowiedź :

Twierdzenie Pitagorasa:

a^2 + b^2 = c^2

Zadanie 2

a) 5^2 + 4^2 = x^2

25 + 16 = x^2

41 = x^2

x = [tex]\sqrt{41}[/tex]

b) 1^2 + y^2 = 5[tex]\sqrt{2}[/tex]^2

25 * 2 - 1 = y^2

50 - 1 = y^2

y^2 = 49

y = [tex]\sqrt{49} = 7[/tex]

c) 4^2 + z^2 = 7^2

49 - 16 = z^2

33 = z^2

z = [tex]\sqrt{33}[/tex]

Zadanie 3

a) 15^2 + a^2 = 17^2

289 - 225 = a^2

a^2 = 64

a = [tex]\sqrt{64} = 8[/tex]

b) 3^2 + 4[tex]\sqrt{10}[/tex]^2 = b^2

9 + 16 * 10 = b^2

b^2 = [tex]\sqrt{169} = 13[/tex]