Odpowiedź:
[tex]\dfrac{-30\cdot(-0,5)^2+(-30)}{-0,1\cdot[-29,4+9\cdot(-0,9)]}=\dfrac{-30\cdot0,25-30}{-0,1\cdot(-29,4-8,1)}=\dfrac{-7,5-30}{-0,1\cdot(-37,5)}=\\\\\\=\dfrac{-37,5}{3,75}=-10[/tex]
[tex]lub\\\\\dfrac{-30\cdot(-0,5)^2+(-30)}{-0,1\cdot[-29,4+9\cdot(-0,9)]}=\dfrac{-30\cdot(-\frac{1}{2})^2-30}{-\frac{1}{10}\cdot(-29,4-8,1)}=\dfrac{-\not30^1^5\cdot\frac{1}{\not4_{2}}-30}{-\frac{1}{10}\cdot(-37,5)}=\\\\\\=\dfrac{-\frac{15}{2}-30}{\frac{1}{10}\cdot\frac{375}{10}}=\dfrac{-\frac{15}{2}-\frac{60}{2}}{\frac{1}{\not10_{2} }\cdot\frac{\not75^1^5}{2}}=\dfrac{-\frac{75}{2}}{\frac{15}{4}}=-\frac{75}{2}:\frac{15}{4}=-\frac{\not75^5}{\not2_{1}}\cdot\frac{\not4^2}{\not15_{1}}=-5\cdot2=-10[/tex]
