Odpowiedź :
[tex]dane:\\m = 20 \ kg\\Q = 100 \ kJ = 100 \ 000 \ J\\T_1 = 5^{o}C\\T_2 = 15^{o}C\\\Delta T = T_2 - T_1 = 15^{o}C - 5^{o}C = 10^{o}C\\szukane:\\c_{w}= ?\\\\\\c_{w} = \frac{Q}{m\cdot \Delta T}\\\\c_{w} = \frac{100000 \ J}{20 \ kg\cdot10^{o}C}\\\\\underline{c_{w} = 500\frac{J}{kg\cdot^{o}C}}[/tex]