Odpowiedź :
[tex]dane:\\m = 3 \ kg\\v = 20\frac{m}{s}\\E_{k} = ?\\\\\\E_{k} = \frac{1}{2}mv^{2}\\\\E_{k} = \frac{1}{2}\cdot3 \ kg\cdot(20\frac{m}{s})^{2}\\\\\underline{E_{k} = 600 \ J}[/tex]
[tex]dane:\\m = 3 \ kg\\v = 20\frac{m}{s}\\E_{k} = ?\\\\\\E_{k} = \frac{1}{2}mv^{2}\\\\E_{k} = \frac{1}{2}\cdot3 \ kg\cdot(20\frac{m}{s})^{2}\\\\\underline{E_{k} = 600 \ J}[/tex]