Odpowiedź:
Wyjaśnienie:
a.
NH₃*H₂O ⇄ NH₄⁺ + OH⁻
K = [OH⁻]*[NH₄⁺]/[NH₃*H₂O]
[OH⁻] = [NH₄⁺]
[NH₃*H₂O] = C
K = [OH⁻]²/ C
C = [OH⁻]²/K
pH = 10 to pOH = 4
[OH⁻] = 10⁻⁴
C = (10⁻⁴)²/1.8*10⁻⁵
C = 0,56*10⁻³mol/dm³= 5,6*10⁻⁴mol/dm³
b.
H₂SO₄ to mocny kwas czyli C = [H⁺]
H₂SO₄ =[H₂O]= 2H⁺ + SO₄²⁻
[H⁺] = 2C
[H⁺] = 2*0,005 = 0,01mol/dm³ = 10⁻²mol/dm³
pH = -log(10⁻²)
pH = 2
