[tex]-1\frac{3}{4}\cdot1,6 = -1\frac{75}{100}\cdot1,6 = -1,75\cdot1,6 = -2,8\\\\(-\frac{3}{5})^{3} = (-\frac{3}{5})\cdot(-\frac{3}{5})\cdot(-\frac{3}{5}) = -\frac{27}{125}\\\\0,26\cdot(-\frac{1}{13})\cdot(-10) =\frac{26}{100}\cdot\frac{10}{13} = \frac{2}{10} = 0,2[/tex]
