Zadanie
d₁ = 12 cm
d₂ = 16 cm
h = 2·d₁ + 2·d₂
h = 2 · 12 + 2 · 16 = 24 + 32 = 56 cm
Pole podstawy
[tex]P_p=\frac{d_1\cdot d_2}{2}\\\\P_p=\frac{12\cdot16}{2}=6\cdot16=96 cm^{2}[/tex]
Pole boczne
Pb= 2·d₁·h + 2·d₂·h
Pb = 2 · 12 · 56 + 2 · 16 · 56 = 3136 cm²
Pole całkowite
Pc = 2·Pp + Pb
Pc = 2 · 96 + 3136 = 192 + 3136 = 3328 cm²
