[tex]dane:\\S_1 = 20 \ cm^{2}\\F_1 = 200 \ N\\S_2 = 80 \ cm^{2}}\\szukane:\\F_2 = ?\\\\Rozwiazanie\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2} = p = constans\\\\F_1\cdot S_2 = F_2\cdot S_1 \ \ /:S_1\\\\F_2 = F_1\cdot\frac{S_2}{S_1}\\\\F_2 = 200 \ N\cdot\frac{80 \ cm^{2}}{20 \ cm^{2}}\\\\F_2 = 200 \ N\cdot4 = 800 \ N[/tex]
Odp. Na duży tłok działa siła o wartości 800 N.
