Odpowiedź:
[tex]y=x^2-6x+5\\\\f(x)=0\\\\x^2-6x+5=0\\\\\Delta=b^2-4ac=(-6)^2-4*1*5=36-20=16\\\\\sqrt{\Delta}=\sqrt{16}=4\\\\\\x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4}{2*1}=\frac{6-4}{2}=\frac{2}{2}=1\\\\\\x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4}{2*1}=\frac{6+4}{2}=\frac{10}{2}=5\\\\\\f(x)=a(x-x_{1})(x-x_{2})\\\\f(x)=1(x-1)(x-5)\\\\f(x)=(x-1)(x-5)[/tex]
