Odpowiedź :
8x-x(x-6)+(x²-3)=6(x+1)-x(x-8)
8x - x² + 6x + x² - 3 = 6x + 6 - x² + 8x
8x - x² + 6x + x² - 6x + x² - 8² = 6 + 3
x² = 9
[tex]x = \sqrt{9} [/tex]
x = 3
8x-x(x-6)+(x²-3)=6(x+1)-x(x-8)
8x - x² + 6x + x² - 3 = 6x + 6 - x² + 8x
8x - x² + 6x + x² - 6x + x² - 8² = 6 + 3
x² = 9
[tex]x = \sqrt{9} [/tex]
x = 3