Odpowiedź:
[tex]\dfrac{\frac{6}{11}-\frac{15}{45}}{\frac{11}{3}-2\frac{1}{2}}*2\frac{3}{4}=\dfrac{\frac{6}{11}-\frac{1}{3}}{\frac{11}{3}-\frac{5}{2}}*\frac{11}{4}=\dfrac{\frac{18}{33}-\frac{11}{33}}{\frac{22}{6}-\frac{15}{6}}*\frac{11}{4}=\dfrac{\frac{7}{33}}{\frac{7}{6}}*\frac{11}{4}=\frac{7}{33}:\frac{7}{6}*\frac{11}{4}=\\\\\\=\frac{\not7^1}{\not33_{11}}*\frac{\not6^2}{\not7_{1}}*\frac{11}{4}=\frac{\not2^1}{\not11_{1}}*\frac{\not11^1}{\not4_{2}}=\frac{1}{2}[/tex]
