Odpowiedź :
[tex]\frac{6cos\alpha+4sin\alpha}{cos\alpha}=8\\\\\frac{6cos\alpha}{cos\alpha}+\frac{4sin\alpha}{cos\alpha}=8\\\\6+4tg\alpha=8\\\\4tg\alpha=8-6\\\\4tg\alpha=2\ \ \ |:4\\\\tg\alpha=\frac{1}{2}[/tex]
[tex]\frac{6cos\alpha+4sin\alpha}{cos\alpha}=8\\\\\frac{6cos\alpha}{cos\alpha}+\frac{4sin\alpha}{cos\alpha}=8\\\\6+4tg\alpha=8\\\\4tg\alpha=8-6\\\\4tg\alpha=2\ \ \ |:4\\\\tg\alpha=\frac{1}{2}[/tex]