[tex]\frac{4,2y^{2}+1,8y+1}{6} = \frac{4,2y^{2}}{6}+\frac{1,8y}{6} + \frac{1}{6} = 0,7y^{2}+0,3y + \frac{1}{6}=\frac{7}{10}y^{2}+\frac{3}{10}y + \frac{1}{6}[/tex]
