[tex]dane:\\Q = 8 \ kJ = 8 \ 000 \ J\\m = 30 \ g = 0,03 \ kg\\T_1 = 1^{o}C\\T_2 = 10^{o}C\\\Delta T = T_2 - T_1 = 10^{o}C - 1^{o}C = 9^{o}C\\szukane:\\c = ?\\\\Rozwiazanie\\\\c = \frac{Q}{m\cdot \Delta T}\\\\c = \frac{8000 \ J}{0,03 \ kg\cdot9^{o}C} =29 \ 630 \ \frac{J}{kg\cdot^{o}C}[/tex]
