Odpowiedź :
P=500 W
U= 230 V
t=10 min = 600 s = 1/6 h
P=U*I
I=P/U
I=500/230 ≈2,17 A
P= W/t
W=P*t
W=500*600= 300000 J
W=500*(1/6) ≈ 83,3 Wh ≈0,0833 kWh
P=500 W
U= 230 V
t=10 min = 600 s = 1/6 h
P=U*I
I=P/U
I=500/230 ≈2,17 A
P= W/t
W=P*t
W=500*600= 300000 J
W=500*(1/6) ≈ 83,3 Wh ≈0,0833 kWh