Odpowiedź :
[tex]0,9a - 1,5 = 17 \ \ |\cdot10\\\\9a - 15 = 170\\\\9a = 170+15\\\\9a = 185 \ \ /:9\\\\a = \frac{185}{9} = 20\frac{5}{9}[/tex]
[tex]Spr.\\\\L = 0,9\cdot\frac{185}{9}-1,5 = 18,5-1,5 = 17 = P[/tex]
[tex]0,9a - 1,5 = 17 \ \ |\cdot10\\\\9a - 15 = 170\\\\9a = 170+15\\\\9a = 185 \ \ /:9\\\\a = \frac{185}{9} = 20\frac{5}{9}[/tex]
[tex]Spr.\\\\L = 0,9\cdot\frac{185}{9}-1,5 = 18,5-1,5 = 17 = P[/tex]