Odpowiedź:
poziom b
a)3(ab+2a)=3ab+6a
b)(3d-9)*(-1)=-3d+9
c)(-3d+8)*4=-12d+32
d)-3*(x+7)=-3x-21
e)(x-5)*2=2x-10
f)-4*(a-3)=-4a+12
g)(2cd-3)*8=16cd-24
h)(xy+y)*(-2)=-2xy-2y
poziom c
a)(10x-5y+1):5=[tex]\frac{10x-5y+1}{5}=\frac{5(2x-1y)+1}{5}=2x-1y+\frac{1}{5}[/tex]
b)[tex]\frac{2a-6ab}{2}=\frac{2(a-3ab)}{2}=a-3ab[/tex]
c)[tex](12p-9r-2):3=4p-3r-\frac{2}{3}[/tex]
d)[tex]\frac{4g-8h+1}{2}=2g-4h+\frac{1}{2}[/tex]
e)(3m+6):6=[tex]\frac{3}{6}m+1=\frac{1}{2}m+1[/tex]
f)[tex]\frac{8t-4s}{4}=\frac{4(2t-1s)}{4}=2t-1s[/tex]
poziom d
a)2(x-8)-3(y-2x²)=2x-16-3y+6x²=6x²+2x-3y-16
b)[tex]\frac{9a+3b}{3}-\frac{4a-8b}{2}+a=\frac{3(3a+1b)}{3}-\frac{2(2a-4b)}{2}+a=3a+1b-2a+4b+a=2a+5b[/tex]
c)-5(p-r+4)-(3r-5p)+16=-5p+5r-20-3r+5p+16=2r-4
d)[tex]\frac{4t-8}{4}+(-6t+2s-1):2=\frac{4(t-2)}{4}+\frac{-6t+2t-1}{2}=t-2-3t+1s-\frac{1}{2}=-2t-2,5+1s[/tex]
e)-6x-(3x-y)+4(-2x+y)=-6x-3x+y-8x+4y=-17x+5y
f)[tex]\frac{12g+4}{2}-\frac{10g-1}{5}=\frac{2(6g+2)}{2}-\frac{5(2g-\frac{1}{5}}{5}=6g+2-2g+\frac{1}{5}=4g+2\frac{1}{5}[/tex]
Szczegółowe wyjaśnienie:
