Wyznacz iloczyn
[tex]( \times - 1 {)}^{2} ( \times + 3)[/tex]


Odpowiedź :

(x-1)²(x+3)=(x²-2x+1)(x+3)=x³+3x²-2x²-6x+x+3=x³+x²-5x+3

[tex](x-1)^{2}(x+3) = (x^{2}-2x+1)(x+3) =x^{3}-2x^{2}+x + 3x^{2}-6x+3 = x^{3}+x^{2}-5x+3[/tex]

(a - b)² = a² - 2ab + b²